Calculate the wave number corresponding to the most energetic spectral line

[atsum]

Calculate the wave number corresponding to the most energetic spectral line in the Lyman series for the hydrogen atom.
Express your answer to six significant figures and include the appropriate units.

I use the formula:
http://i.imgur.com/YgLVY.jpg

Because the question asks the most energetic one, so
[wave number = Rydberg's constant/h/c]
I got the answer10974214m-1
But the answer is wrong.
What's wrong with my calculation?

 

[Borek]

What makes you think the answer is wrong?

 

[atsum]

What makes you think the answer is wrong?

I did it in MasteringChemistry. It says the answer is wrong.

 

[Borek]

If you are given Rydberg's constant with three significant figures, you can't give the answer with eight.

Not that I am sure that's the problem, but it surely can be one.

 

[DeeNos]

Your calculation is incorrect because you have used the Rydberg's constant for the entire hydrogen atom, rather than just the Lyman series. The correct formula to use is:
wave number = R(1/n1^2 - 1/n2^2)
Where R is the Rydberg's constant for the Lyman series (1.0973731568539 x 10^7 m^-1), n1 is the initial energy level (1 for the Lyman series), and n2 is the final energy level (2 for the most energetic line in the Lyman series).
Plugging in these values, we get:
wave number = (1.0973731568539 x 10^7 m^-1)(1/1^2 - 1/2^2) = 1.0973731568539 x 10^7 m^-1
Therefore, the correct wave number for the most energetic spectral line in the Lyman series for the hydrogen atom is 1.0973731568539 x 10^7 m^-1, expressed to six significant figures.