- #1
ramox3
- 12
- 0
Hello everyone I am a newbie to electrical engineering, I have this problem I've been strugling with, no textbook seems to cover this problem..A three-phase, 440-V, generator delivers 5400W of active power through two recti-fies, A and B, into a three-phase, 230-V, line as shown in Figure 3.
The dc current through the inductor is 20A. If power loss in both rectifiers are negligible, calculate:
(a). Firing angle of the rectifier A;
(b). Firing angle of the rectifier (inverter) B.
This is my attempt ;
V out = 5400/ 20 = 270
For inductive load
VOUT = 1.35 × VLINE × cos α
Where ‘α’ is the firing angle of the rectifier.
Therefore,
cos α = V / 1.35 x Vline
α = 29
how does this seem? and how is the inverter's firing angle different?
The dc current through the inductor is 20A. If power loss in both rectifiers are negligible, calculate:
(a). Firing angle of the rectifier A;
(b). Firing angle of the rectifier (inverter) B.
This is my attempt ;
V out = 5400/ 20 = 270
For inductive load
VOUT = 1.35 × VLINE × cos α
Where ‘α’ is the firing angle of the rectifier.
Therefore,
cos α = V / 1.35 x Vline
α = 29
how does this seem? and how is the inverter's firing angle different?