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Gear2d
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Homework Statement
In an ideal fluid, the pipe length is doubled, while radius is decreased by factor 2 what will have to the velocity and volume that is flowing?
Homework Equations
Q=Av = pi*r^2*v
The Attempt at a Solution
From this the volume that will pass, in ideal fluid cases, is constant (same throughout), but the velocity will increase by a factor of 4 since: Q/v = pi*r^2. Is this correct?
Also if I were considering the radius decreasing by a factor of 2, in real fluids, the velocity would increase by it would not increase as much as seen in ideal fluids?