- #1
reenmachine
Gold Member
- 514
- 8
Hi all , here's hoping someone could help me with this problem. :)
The problem is basically as follow:
You have 7 balls in your pocket , 3 are whites and 4 are blacks.If you take out 3 balls out of your pocket , what are the odds that you'll have 2 white balls and 1 black ball in your hand ?
Now I have no mathematic education at all so here's how I proceeded:
3/7 * (1/2 + 1/3) * (1/5 + 2/5 + 3/5)
3/7 * 5/6 * 5/5
3/7 * 5/6 = 5/14
5/14 = 35,7% = 36%
That was my final answer and I got it wrong , the answer happened to be 34%.
How could my method of calculating the odds produce an answer that was so close yet wrong?
Help would be greatly appreciated :D
thanks in advance
The problem is basically as follow:
You have 7 balls in your pocket , 3 are whites and 4 are blacks.If you take out 3 balls out of your pocket , what are the odds that you'll have 2 white balls and 1 black ball in your hand ?
Now I have no mathematic education at all so here's how I proceeded:
3/7 * (1/2 + 1/3) * (1/5 + 2/5 + 3/5)
3/7 * 5/6 * 5/5
3/7 * 5/6 = 5/14
5/14 = 35,7% = 36%
That was my final answer and I got it wrong , the answer happened to be 34%.
How could my method of calculating the odds produce an answer that was so close yet wrong?
Help would be greatly appreciated :D
thanks in advance