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phyBnewb
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Homework Statement
A parallel-plate capacitor consists of two square plates, size L x L, separated by distance d. The plates are given charge +-Q . Each part changes only one quantity; the other quantities have their initial values.
Part A
What is the ratio E(final)/E(initial) of the final to initial electric field strengths if Q is doubled?
Homework Equations
I know that:E = kQ/r^2 ,where k= 8.99*10^9
The Attempt at a Solution
I am not sure where to start here for this question.
Since it is a ratio of E final / E initial would Q cause E to be something like this?
E = k(2Q)/r^2 => 1/2E for E final?