- #1
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I saw this thing where someone proved that the imaginary number, i, the sqrt(-1) was equal to 1.
here it is:
i= sqrt(-1)
i^2 = [sqrt(-1)]^2
i^2 = sqrt(-1) * sqrt(-1)
i^2 = sqrt(-1*-1)
i^2 = sqrt(1)
i^2 = 1
so
i = 1
I know there's something wrong here but i can't figure it out. any help?
here it is:
i= sqrt(-1)
i^2 = [sqrt(-1)]^2
i^2 = sqrt(-1) * sqrt(-1)
i^2 = sqrt(-1*-1)
i^2 = sqrt(1)
i^2 = 1
so
i = 1
I know there's something wrong here but i can't figure it out. any help?