- #1
wanchosen
- 19
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I have been looking at this question from a Mechanics Chapter:-
A stone is thrown vertically upwards with a velocity of u metres per second. It passes a ledge in t1 seconds and repasses it t2 seconds after the start. Find the height of the ledge?
Take g = 9.8 metres per second sq
This is the question in entirety.
I have tried using
s = ut + 1/2 a t^2 substituting g in as
s = ut - 1/2 g t^2
If the height is the same at both these times then I have assumed that:-
ut1 -1/2 g t1^2 = ut2 - 1/2 g t2^2
Then factoring out t1 and t2
t1(u - 1/2 g t1) = t2(u - 1/2 g t2)
then failed to see how this could find s!
Then tried rearranging the original formula in terms of u and t1, so:
u = (s + 1/2 g t1^2)/t1
and substituting into
s = ut2 - 1/2 g t2^2
but couldn't proceed.
Can somebody help? I am assuming that I need to find s in terms of g, t1 and t2 rather than an actual value.
A stone is thrown vertically upwards with a velocity of u metres per second. It passes a ledge in t1 seconds and repasses it t2 seconds after the start. Find the height of the ledge?
Take g = 9.8 metres per second sq
This is the question in entirety.
I have tried using
s = ut + 1/2 a t^2 substituting g in as
s = ut - 1/2 g t^2
If the height is the same at both these times then I have assumed that:-
ut1 -1/2 g t1^2 = ut2 - 1/2 g t2^2
Then factoring out t1 and t2
t1(u - 1/2 g t1) = t2(u - 1/2 g t2)
then failed to see how this could find s!
Then tried rearranging the original formula in terms of u and t1, so:
u = (s + 1/2 g t1^2)/t1
and substituting into
s = ut2 - 1/2 g t2^2
but couldn't proceed.
Can somebody help? I am assuming that I need to find s in terms of g, t1 and t2 rather than an actual value.