- #1
cwesto
- 18
- 0
Homework Statement
Homework Equations
P=IV
I=V/R
P=(V/R)V
R=V2/R
The Attempt at a Solution
PR1: 122/12=12
PR2: 144/18
I'm not sure what to do from here. Thanks for any input and help!
cwesto said:I=V/R
Rtotal=12+18
I=12/30
PR1=RI2
PR1=12*[tex]\frac{2}{5}[/tex]*[tex]\frac{2}{5}[/tex]
PR1=48/25
PR2=[tex]\frac{72}{25}[/tex]=2.88
Thanks!
The dissipation of power by resistors refers to the process of converting electrical energy into heat energy when an electric current passes through a resistor. This heat energy is a result of the resistance of the material in the resistor to the flow of electrons.
The power dissipation by resistors can affect the circuit in several ways. It can cause the resistor to heat up, which can change its resistance and potentially damage the component. It can also cause a voltage drop across the resistor, which can affect the overall performance of the circuit. Additionally, the dissipation of power can cause a decrease in the overall efficiency of the circuit.
The dissipation of power by resistors can be affected by several factors, including the resistance value, the current flowing through the resistor, and the temperature of the resistor. The type of material and the physical size of the resistor can also affect its power dissipation.
The dissipation of power by resistors can be calculated using the formula P = I^2 * R, where P is the power dissipation in watts, I is the current in amperes, and R is the resistance in ohms. This formula is known as Joule's law and can be used to determine the amount of heat energy being dissipated by a resistor.
The dissipation of power by resistors can be reduced by using resistors with higher power ratings, which can handle more heat without getting damaged. Additionally, using resistors with lower resistance values can also help reduce power dissipation. Proper heat sinking and ventilation can also help dissipate the heat generated by resistors.