- #1
physics1234
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A 55 g ice cube at 0°C is heated until 40 g has become water at 100°C and 15 g has become steam at 100°C. How much energy was added to accomplish the transformation?
I tried using Q=mL for each change and adding them together.
Q=.055(3.33x10^5)
Q=18315
then
Q=.015(2.26x10^6)
Q=33900
18315+33900= 52215 which is not the correct answer.
I tried using Q=mL for each change and adding them together.
Q=.055(3.33x10^5)
Q=18315
then
Q=.015(2.26x10^6)
Q=33900
18315+33900= 52215 which is not the correct answer.