- #1
krackers
- 72
- 0
Lets assume you're given
[itex]{ 3x }^{ 2 }+8x-11[/itex]
And you want to factor it. With the AC method you multiple 3 and -11 giving you -33. Then you find the factors of -33 that add up to 8. 11 and -3, in this case. Then you rewrite the quadratic as
[itex]{ 3x }^{ 2 }-3x+11x-11[/itex]
From there, you factor each part independently giving:
3x(x-1)+11(x-1)
And finally, factor out (x-1) to get:
(3x+11)(x-1).
However, I do not have any understanding as to how this works.
Thanks
[itex]{ 3x }^{ 2 }+8x-11[/itex]
And you want to factor it. With the AC method you multiple 3 and -11 giving you -33. Then you find the factors of -33 that add up to 8. 11 and -3, in this case. Then you rewrite the quadratic as
[itex]{ 3x }^{ 2 }-3x+11x-11[/itex]
From there, you factor each part independently giving:
3x(x-1)+11(x-1)
And finally, factor out (x-1) to get:
(3x+11)(x-1).
However, I do not have any understanding as to how this works.
Thanks