- #1
kappcity06
- 90
- 0
A car traveling at 16.0 m/s runs out of gas while traveling up a 21.0 degree slope.
How far up the hill will it coast before starting to roll back down?
I tried
1/2mv^2=mgh
1/2(16)^2=9.8h
13.06=h
can anyone confirm if this is correct or not. I;m not sure if I have to use trig to solve this or not.
help please.
How far up the hill will it coast before starting to roll back down?
I tried
1/2mv^2=mgh
1/2(16)^2=9.8h
13.06=h
can anyone confirm if this is correct or not. I;m not sure if I have to use trig to solve this or not.
help please.