- #1
Reshma
- 749
- 6
An electron of mass 'm' and speed 'v' collides with a gamma ray photon of initial energy hf0, as measured from the laboratory frame. The photon is scattered in the electron's direction of travel. Verify that the energy of the scattered photon, as measured in the laboratory frame, is:
[tex]E = hf_0\left(1 + \frac{2hf_0}{mc^2}\sqrt{\frac{1 + v/c}{1 - v/c}}\right)^{-1}[/tex]
Well this also seems to be a Compton effect problem. The relativistic Doppler equation for frequency is given by:
[tex]f = f_0\sqrt{\frac{1 - \beta}{1 + \beta}}[/tex]
where [itex]\beta = v/c[/itex]
Need guidance to apply this formula to obtain above result...
[tex]E = hf_0\left(1 + \frac{2hf_0}{mc^2}\sqrt{\frac{1 + v/c}{1 - v/c}}\right)^{-1}[/tex]
Well this also seems to be a Compton effect problem. The relativistic Doppler equation for frequency is given by:
[tex]f = f_0\sqrt{\frac{1 - \beta}{1 + \beta}}[/tex]
where [itex]\beta = v/c[/itex]
Need guidance to apply this formula to obtain above result...