- #1
snoopies622
- 846
- 28
Is there any particular reason that scalar curvature is defined [tex] R = g^{ab}R_{ab} [/tex] instead of [tex] R = R^{ab}R_{ab} [/tex] ?
Do both scalars share the property that they are zero if and only if every component of [itex] R^{a}_{bcd} [/itex] is also zero?
Do both scalars share the property that they are zero if and only if every component of [itex] R^{a}_{bcd} [/itex] is also zero?