- #1
Ed Quanta
- 297
- 0
So if we let x>0, For which 0<p<=infinity is {1/n^x} an element of l^p?
If x=1, then 1/n^x is clearly an element of l^p for p>=2, since for all these vector spaces, the series of 1/n will converge?
But if x<1, then in it seems that only for p=infinity, will {1/n^x} be an element of l^p. Is this correct?
If x=1, then 1/n^x is clearly an element of l^p for p>=2, since for all these vector spaces, the series of 1/n will converge?
But if x<1, then in it seems that only for p=infinity, will {1/n^x} be an element of l^p. Is this correct?