- #1
eranium
- 4
- 0
Hello people,
i have been wondering if translational K.E = 3/2 RT, where T is the temperature, why is it that when we place a cup of water in a fast moving jet, the Temperature still remains the same, even though the K.E of the cup of water increases (due to the velocity of the jet)
would appreciate if someone help clear some doubts,
thanks in advance!
i have been wondering if translational K.E = 3/2 RT, where T is the temperature, why is it that when we place a cup of water in a fast moving jet, the Temperature still remains the same, even though the K.E of the cup of water increases (due to the velocity of the jet)
would appreciate if someone help clear some doubts,
thanks in advance!