- #1
sgstudent
- 739
- 3
When I throw a ball up in the air, my acceleration will still be -10m/s^2 right? Just that my original upwards force before I release it will result in a greater upwards speed, then when the hand stops producing the force, the weight will result in a -10m/s^2 causing a deceleration and eventual a downwards acceleration of 10m/s^2 right?
Then when I throw a ball down from a building. In addition to the force acting downwards there is weight, so at the point my acceleration is more than 10m/s^2. Then when I release the ball, I have a decreased force. So will the acceleration start to decrease to 10m/s^2? So that means I will increase in speed but now in a slower rate as the ball goes down?
Thanks for the help!
Then when I throw a ball down from a building. In addition to the force acting downwards there is weight, so at the point my acceleration is more than 10m/s^2. Then when I release the ball, I have a decreased force. So will the acceleration start to decrease to 10m/s^2? So that means I will increase in speed but now in a slower rate as the ball goes down?
Thanks for the help!