- #1
mhill
- 189
- 1
if we consider the propagators and other Fourier integrals in the sense of 'distribution' then are all the divergences that appear in QFT (quantum field theory) due to the divergent quantities
[tex] \delta ^{k} (0) [/tex]
that is my idea, all the divergences appear because in the commutation relations
[tex] [\Psi (x) , \Psi (y) ] = \delta (x-y) [/tex]
appear the dirac delta function an its derivatives, or in the mathematical sense all the divergencies are proportional to the 'value'
[tex] \delta ^{k} (0) [/tex] , here 'k' means the k-th derivative of the delta function
[tex] \delta ^{k} (0) [/tex]
that is my idea, all the divergences appear because in the commutation relations
[tex] [\Psi (x) , \Psi (y) ] = \delta (x-y) [/tex]
appear the dirac delta function an its derivatives, or in the mathematical sense all the divergencies are proportional to the 'value'
[tex] \delta ^{k} (0) [/tex] , here 'k' means the k-th derivative of the delta function