- #1
Ryoukomaru
- 55
- 0
Use subs [tex]y=xv[/tex] to show that [tex](x^2+y^2)+2xy\frac{dy}{dx}=0, x>0[/tex] is [tex] x^3+3xy^2=k[/tex] where k is a constant.
I played around with this at school and if memory serves me correct i got something similar to [tex]\frac{dx}{dv}=\frac{-3}{2xv}-\frac{1}{2}[/tex] and after that i decided i wasnt on the right path and stopped. Need a little help here !
I played around with this at school and if memory serves me correct i got something similar to [tex]\frac{dx}{dv}=\frac{-3}{2xv}-\frac{1}{2}[/tex] and after that i decided i wasnt on the right path and stopped. Need a little help here !