- #1
jason_mcc
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Homework Statement
Hi everyone. All help is appreciated.
The discharge over a rectangular notch is to be 0.14m3/sec when the water level is 0.23m above the sill. If the coefficient of discharge is 0.6 calculate the width of notch required.
Answer: 0.716m
Homework Equations
I think it is Q=[tex]\frac{2}{3}[/tex]b[tex]\sqrt{2g}[/tex]H[tex]^{\frac{2}{3}}[/tex]Cd
where Q=flow rate, H=height of water level above bottom of notch, b=width of notch.
The Attempt at a Solution
Q=[tex]\frac{2}{3}[/tex]b[tex]\sqrt{2g}[/tex]H[tex]^{\frac{2}{3}}[/tex]Cd
0.14=[tex]\frac{2}{3}[/tex]b[tex]\sqrt{2g}[/tex]0.23[tex]^{\frac{2}{3}}[/tex]0.6
0.14= 2/3 x b x 4.429 x 0.375 x 0.6
0.14= 0.664 b
b= 0.21m
which is wrong. Anyone know what I'm doing wrong?