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get_rekd
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A coal power plant with three power generators is used to power a small city. If each generator uses 1.22 X 10^8 J of chemical energy in the coal every hour, and the average annual energy consumption of the city is 1.61 X 10^12 J. What is the efficiency of the generators?
(Assume the generators run 24 hours a day 365 days a year)
SO here's what I've got so far:
(1.22 X 10^8 J)(3 generators)= 3.6 X 10^8 J used per hour for 3 generators.
(3.6 X 10^8 J)(24H)= 8.6 X 10^9 J consumed in 24 Hours or 1 Day.
(8.6 X 10^9 J)(365 Days)= 3.14 X 10^12 J consumed per year.
So I know how much energy the generators consume but how do I figure out the annual energy output of the generators, and what kind of energy would it be?
1.61 X 10^12 J= Cities annual energy consumption
(Assume the generators run 24 hours a day 365 days a year)
SO here's what I've got so far:
(1.22 X 10^8 J)(3 generators)= 3.6 X 10^8 J used per hour for 3 generators.
(3.6 X 10^8 J)(24H)= 8.6 X 10^9 J consumed in 24 Hours or 1 Day.
(8.6 X 10^9 J)(365 Days)= 3.14 X 10^12 J consumed per year.
So I know how much energy the generators consume but how do I figure out the annual energy output of the generators, and what kind of energy would it be?
1.61 X 10^12 J= Cities annual energy consumption