- #1
courtrigrad
- 1,236
- 2
Hello all
I have a few questions on applied maxima and minima
1. A company gives you 675 sq. ft of cardboard to construct a rectangular carton with the largest volume. If the carton is to have a square base and an open top, what dimensions would you use?
My Thought Process:
Volume = length * width * height
= x*x* (675- 2x)
I know how to find the maximum volume, but am not sure about the actual equation. If it has a square base, then shouldn't it be x*x *( 675 - 2x)
Any help is greatly appreciated
Thanks
I have a few questions on applied maxima and minima
1. A company gives you 675 sq. ft of cardboard to construct a rectangular carton with the largest volume. If the carton is to have a square base and an open top, what dimensions would you use?
My Thought Process:
Volume = length * width * height
= x*x* (675- 2x)
I know how to find the maximum volume, but am not sure about the actual equation. If it has a square base, then shouldn't it be x*x *( 675 - 2x)
Any help is greatly appreciated
Thanks