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thestormbreaker
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I need help with finding an equation of a graph. I was wondering if anyone was able to give me an equation to a graph that has a turning point at (0,0) (or a gradient of zero at (0,0)) and a turning point at (60,10). It would be great if you could show you basic working out so I can see how you came to your answer.
y=7.7*10^7 (x)^2) (x - 120)^2 This is one in quartic
y=4.6*10^-5 (x)^2 (x-120) This is one in cubic
There is more than one answer and I was hoping for as many as people could come up with.
If anyone could help it was be very much appreciated.
Thanks
y=7.7*10^7 (x)^2) (x - 120)^2 This is one in quartic
y=4.6*10^-5 (x)^2 (x-120) This is one in cubic
There is more than one answer and I was hoping for as many as people could come up with.
If anyone could help it was be very much appreciated.
Thanks
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