- #1
emilinus
- 15
- 0
umm this question seems simple enough but I don't really know what I'm doing...
A chain consisting of 5 links, each of mass .100 kg is lifted vertically upwards with a constant acceleration of 2.50 m/s^2. Calculate the force that link 2 exerts on link 1.
so what I did was add the masses of links 2-5 (m=0.4 kg) and multiply this by the acceleration.
so my answer is F21 = 1 N
I have no idea if this is even close to what I'm supposed to do.
Help would be appreciated, thanks.
A chain consisting of 5 links, each of mass .100 kg is lifted vertically upwards with a constant acceleration of 2.50 m/s^2. Calculate the force that link 2 exerts on link 1.
so what I did was add the masses of links 2-5 (m=0.4 kg) and multiply this by the acceleration.
so my answer is F21 = 1 N
I have no idea if this is even close to what I'm supposed to do.
Help would be appreciated, thanks.