- #1
trajan22
- 134
- 1
the main problem I am having is i can't figure out how they simplified this equation. Ill try and use latex but its my first time so i don't know if it will work.
[tex]
\int(1-\frac{1}{3(x+1)}+\frac{(x-2)}{3(x^2-x+1)}) dx
[/tex]
and somehow this simplifies to this
[tex]
x- (1/3)ln(abs(x+1)) +(1/6) \int \frac{(2x-1)}{(x^2-x+1)} dx - (1/2) \int \frac{(dx)}{(x-.5)^2+(3/4)}
[/tex]
i understand how to get the x-(1/3)ln(2x-1) but i don't get how they separated the other two terms for integration. or how they pulled out (1/6)
[tex]
\int(1-\frac{1}{3(x+1)}+\frac{(x-2)}{3(x^2-x+1)}) dx
[/tex]
and somehow this simplifies to this
[tex]
x- (1/3)ln(abs(x+1)) +(1/6) \int \frac{(2x-1)}{(x^2-x+1)} dx - (1/2) \int \frac{(dx)}{(x-.5)^2+(3/4)}
[/tex]
i understand how to get the x-(1/3)ln(2x-1) but i don't get how they separated the other two terms for integration. or how they pulled out (1/6)
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