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Vitalik
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1. What will be the multiplicity due to spin-spin splitting of the highlighted protons in the molecule: (C6H5)-CH2-CH2-CH2-OH?
None
I know that the ones surrounding the highlighted CH2 group are not equivalent. If they were, the multiplicity would be 5. When I make a branching diagram, I get 6 to a multiplet. In the textbook, there was an example of a similar case where you could "assume" that they were equal, even though they were not. How do I know if I can "assume" in this case? My answer choices are a) doublet b) triplet c) quartet d) quintet e) hextet. I'm stuck between d) a quintet, if I assume that they are equal and e) the minimum, probably, but couldn't a multiplet of more than 6 form also? Any help? Thank you.
Homework Equations
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The Attempt at a Solution
I know that the ones surrounding the highlighted CH2 group are not equivalent. If they were, the multiplicity would be 5. When I make a branching diagram, I get 6 to a multiplet. In the textbook, there was an example of a similar case where you could "assume" that they were equal, even though they were not. How do I know if I can "assume" in this case? My answer choices are a) doublet b) triplet c) quartet d) quintet e) hextet. I'm stuck between d) a quintet, if I assume that they are equal and e) the minimum, probably, but couldn't a multiplet of more than 6 form also? Any help? Thank you.
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