- #1
SclayP
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1. So, i have the next integrand...
2. [itex]\int \frac{1}{(x-1)^2(x+1)^2}\,dx[/itex]
3. I proceeded by resolving it by partial fraction and i came up with the next...
[itex]\int \frac{1}{((x-1)^2)((x+1)^2)}\,dx = \int \frac{A}{(x-1)} + \frac{B}{(x-1)^2} + \frac{C}{(x+1)} + \frac{D}{(x+1)^2}\,dx[/itex]
The thing is that after doing all the calculus i came up with this...
[itex]A + C = 0[/itex]
[itex]A + B - C + D = 0[/itex]
[itex]-A + 2B - C -2D = 0[/itex]
[itex]A + B + C + D = 1[/itex]
After this i don't know how to preceed i mean i don't know how to resolve the equation whit 4 variables...
Thanks, and very sorry for my english...
2. [itex]\int \frac{1}{(x-1)^2(x+1)^2}\,dx[/itex]
3. I proceeded by resolving it by partial fraction and i came up with the next...
[itex]\int \frac{1}{((x-1)^2)((x+1)^2)}\,dx = \int \frac{A}{(x-1)} + \frac{B}{(x-1)^2} + \frac{C}{(x+1)} + \frac{D}{(x+1)^2}\,dx[/itex]
The thing is that after doing all the calculus i came up with this...
[itex]A + C = 0[/itex]
[itex]A + B - C + D = 0[/itex]
[itex]-A + 2B - C -2D = 0[/itex]
[itex]A + B + C + D = 1[/itex]
After this i don't know how to preceed i mean i don't know how to resolve the equation whit 4 variables...
Thanks, and very sorry for my english...
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