- #1
zetafunction
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If i have ONLY logarithmic divergences as [tex] \lambda \rightarrow \infty [/tex] of the form
[tex] log(a+\lambda ^{n}) [/tex] or [tex] log (\lambda ) [/tex] or [tex] log^{k}(\lambda) [/tex] for some real numbers a,n and k HOW many counterterms should i put into de Lagrangian in order to make it FINITE ?? , the idea is let us suppose we use DIMENSIONAL REGULARIZATION so we only had logarithmic divergent integrals (and assuming that power law divergences can be reduced by dimensional regularization or other method to only logarithmic divergences), how many counterterms should i add to the original lagrangian to obtain finite results ??
[tex] log(a+\lambda ^{n}) [/tex] or [tex] log (\lambda ) [/tex] or [tex] log^{k}(\lambda) [/tex] for some real numbers a,n and k HOW many counterterms should i put into de Lagrangian in order to make it FINITE ?? , the idea is let us suppose we use DIMENSIONAL REGULARIZATION so we only had logarithmic divergent integrals (and assuming that power law divergences can be reduced by dimensional regularization or other method to only logarithmic divergences), how many counterterms should i add to the original lagrangian to obtain finite results ??