- #1
elie_girl
- 11
- 0
1. Rationalize the numerator sqrt(5)+3/-4sqrt(7).
(sqrt(5) + 3) / (-4)(sqrt(7)) =
(sqrt(5) + 3)(sqrt(5) - 3) / (-4)(sqrt(7))(sqrt(5) - 3) =
(5 - 9) / (-4)(sqrt(7))(sqrt(5) - 3) =
-4 / (-4)(sqrt(7))(sqrt(5) - 3) =
1 / (sqrt(7))(sqrt(5) - 3)
2. Perform the operation. Write the answer in a + bi form. 3+i/6-i I do this problem and I get the answer (17+9i)/37 is that right?
(3 + i) / (6 - i) =
(3 + i)(6 + i) / (6 - i)(6 + i) =
18 + 9i -1 / 36 + 1
17 + 9i / 37
(sqrt(5) + 3) / (-4)(sqrt(7)) =
(sqrt(5) + 3)(sqrt(5) - 3) / (-4)(sqrt(7))(sqrt(5) - 3) =
(5 - 9) / (-4)(sqrt(7))(sqrt(5) - 3) =
-4 / (-4)(sqrt(7))(sqrt(5) - 3) =
1 / (sqrt(7))(sqrt(5) - 3)
2. Perform the operation. Write the answer in a + bi form. 3+i/6-i I do this problem and I get the answer (17+9i)/37 is that right?
(3 + i) / (6 - i) =
(3 + i)(6 + i) / (6 - i)(6 + i) =
18 + 9i -1 / 36 + 1
17 + 9i / 37