- #1
aisha
- 584
- 0
(3squareroot27)^3x-1=9^x+3
I don't get these questions because I don't know how to get rid or the square root. First I thought Id multiply both sides by the root 3 and then the square root would disappear and i'd be left with (27)^3x-1=(9^x+3)^3 then I found a common base which could be 9? or does it have to be 3? Well I used 9 and when I simplified the exponents I got x=2 but the answer is x=7 can someone help me out please?
I don't get these questions because I don't know how to get rid or the square root. First I thought Id multiply both sides by the root 3 and then the square root would disappear and i'd be left with (27)^3x-1=(9^x+3)^3 then I found a common base which could be 9? or does it have to be 3? Well I used 9 and when I simplified the exponents I got x=2 but the answer is x=7 can someone help me out please?