- #1
Werg22
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If an object starts from a point a certain an amount of time ahead of the other ,how to calculate the minimum amount of time difference for which it is impossible for object 2 to catch up on object 1? This the information;
Object 1 starts at a initial velocity of 0 with a constant acceleration of 1m/s^2.
Object 2 starts at a initial velocity of 4.5m/s with a constant acceleration of 0.
Let the amount of time be u.
Calculating the discplacement of object 1 after u.
d=(u^2)/2
Calculating the final velocity;
v=1u
Now the discplacement of object 2:
d=4.5t
The discplacement of object 1:
d=t^2/2 + ut + (u^2)/2
Now for what value of u,
t^2/2 + ut + (u^2)/2 > 4.5t
for any value of t?
Object 1 starts at a initial velocity of 0 with a constant acceleration of 1m/s^2.
Object 2 starts at a initial velocity of 4.5m/s with a constant acceleration of 0.
Let the amount of time be u.
Calculating the discplacement of object 1 after u.
d=(u^2)/2
Calculating the final velocity;
v=1u
Now the discplacement of object 2:
d=4.5t
The discplacement of object 1:
d=t^2/2 + ut + (u^2)/2
Now for what value of u,
t^2/2 + ut + (u^2)/2 > 4.5t
for any value of t?