- #1
lavster
- 217
- 0
in a many particle system we have a center of mass R and position vector of the ith particle with respect to centre of mass is r_i. hence the position vector measured from the origin is R_i=R+r_i.
why does [tex]R\times\sum (m_i \dot{r}_i) =0[/tex], where [tex]\dot{r}_i[/tex] denotes the rate of change wrt time and m_i is the mass of the ith particle?
thanks
why does [tex]R\times\sum (m_i \dot{r}_i) =0[/tex], where [tex]\dot{r}_i[/tex] denotes the rate of change wrt time and m_i is the mass of the ith particle?
thanks