- #1
pureouchies4717
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this is the question:
i know how to find the average energy:
average energy= (3/2)K(b)T
= 6.21 x 10^-21
i also know how to find the kinetic energy of an oxygen molecule:
K= 1/2 m v(rms)^2
the only problem is that i don't know how to get the distance. can someone please help
From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 300 K?
i know how to find the average energy:
average energy= (3/2)K(b)T
= 6.21 x 10^-21
i also know how to find the kinetic energy of an oxygen molecule:
K= 1/2 m v(rms)^2
the only problem is that i don't know how to get the distance. can someone please help