One of these last 2 equations is correct (do you know which?) There might be a problem with the number of significant figures you gave in your answer, or you could have done the arithmetic wrong. Since you didn't say what answer you got, it's hard to tell.thedarkone80 said:Homework Statement
A man with an 70kg mass, sits on chair of 10kg, and pulls himself upwards at a acceleration of 0.2m/s^2. What is the force needed to achieve this acceleration?
Homework Equations
F=ma
The Attempt at a Solution
F=(80)*(9.81+0.2)
F=(80)*(9.81-0.2)
Neither are giving a correct answer, please help!
thedarkone80 said:no, he is pulling himself and the chair upwards, he is on a pully system. sorry for not being clear. appreciate the quick response though!
The acceleration of 0.2m/s^2 indicates how quickly the man's upward velocity is increasing. This means that he will be able to pull himself up at a faster rate compared to a lower acceleration, but it also requires more effort and energy.
0.2m/s^2 is generally considered a moderate acceleration for a man pulling himself up. It is not extremely slow, but it is also not very fast. This acceleration can vary depending on the strength and technique of the individual.
It is unlikely for a man to sustain a constant acceleration of 0.2m/s^2 while pulling himself up, as it requires a significant amount of strength and energy. It is more common for the acceleration to decrease over time as the man becomes fatigued.
The force applied by the man directly affects the acceleration of 0.2m/s^2. The greater the force, the higher the acceleration will be. This is because force is directly proportional to acceleration according to Newton's Second Law of Motion.
The man's acceleration of 0.2m/s^2 can be affected by various factors such as his strength, technique, body weight, and the friction between his hands and the surface he is pulling himself up on. Other external factors such as gravity and air resistance can also play a role.