- #1
wahaj
- 156
- 2
I am having a little trouble understanding the force of friction. It is given by the formula
Ff = [itex]\mu[/itex]FN
Now taking a mass on an inclined plane with angle θ into consideration, I want to find out what the value for μ. I know what FN is I can easily calculate that but I am having trouble understanding Ff. If the mass has a force acting on it which goes up the inclined plane (The mass is attached to a string which goes trough a pulley located at the top of the inclined plane. The direction of the force applied on the mass will be parallel to the inclined place going up the plane) assuming that the force applied is just enough to overcome the sum of static friction and the parallel component of gravity on the mass, how can I find Ff using the mass and the force acting on the mass?
I am sorry if this is badly worded. please ask for clarification if needed
Ff = [itex]\mu[/itex]FN
Now taking a mass on an inclined plane with angle θ into consideration, I want to find out what the value for μ. I know what FN is I can easily calculate that but I am having trouble understanding Ff. If the mass has a force acting on it which goes up the inclined plane (The mass is attached to a string which goes trough a pulley located at the top of the inclined plane. The direction of the force applied on the mass will be parallel to the inclined place going up the plane) assuming that the force applied is just enough to overcome the sum of static friction and the parallel component of gravity on the mass, how can I find Ff using the mass and the force acting on the mass?
I am sorry if this is badly worded. please ask for clarification if needed