- #1
Zhivago
- 26
- 1
[tex]\sum_{n=1}^{\infty} \frac{o(2^n)}{2^n} = \frac{1}{9} [/tex]
where [tex]o(2^n)[/tex] is the number of odd digits of [tex]2^n[/tex].
Found it in
http://mathworld.wolfram.com/DigitCount.html
equation (9)
where [tex]o(2^n)[/tex] is the number of odd digits of [tex]2^n[/tex].
Found it in
http://mathworld.wolfram.com/DigitCount.html
equation (9)