- #1
jdstokes
- 523
- 1
Can anyone explain to me why
the 3-rep of SU(3) gives
[itex]3\otimes 3 = \overline{3}\oplus 6[/itex]
whereas for the 5 of SU(5)
[itex]5\otimes 5 = 10\oplus 15[/itex]?
I thought the general pattern was
[itex]N \otimes N = \overline{\frac{1}{2}N(N-1)}\oplus \frac{1}{2}N(N+1)[/itex]
but this second example seems to contradict that.
Edit: I wrote 15* instead of 15.
the 3-rep of SU(3) gives
[itex]3\otimes 3 = \overline{3}\oplus 6[/itex]
whereas for the 5 of SU(5)
[itex]5\otimes 5 = 10\oplus 15[/itex]?
I thought the general pattern was
[itex]N \otimes N = \overline{\frac{1}{2}N(N-1)}\oplus \frac{1}{2}N(N+1)[/itex]
but this second example seems to contradict that.
Edit: I wrote 15* instead of 15.
Last edited: