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Digitalx04
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Homework Statement
A car of mass M = 1200 kg traveling at 40.0 km/hour enters a banked turn covered with ice. The road is banked at an angle theta, and there is no friction between the road and the car's tires.
What is the radius r of the turn if [tex]\theta[/tex] = 20.0 degrees (assuming the car continues in uniform circular motion around the turn)?
The Attempt at a Solution
I believe that [tex]F_{c}[/tex] = [tex]F_{N}[/tex] sin ([tex]\theta[/tex]) = m([tex]\frac{v^{2}}{r}[/tex])
Using this I solved for r, which is my missing variable and came up with:
r = [tex]\frac{v^{2}}{F_{N}sin\theta}[/tex]
Using this formula I get
r = [tex]\frac{11.1^{2}}{9.8 sin 20}[/tex]
but when I submitted this answer it told me the normal force is not equal to the weight of the car.
My questions are what is the [tex]F_{N}[/tex] value and am I missing another value in my equation?