- #1
helpmeplz!
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Hey guys i have a question for my lab report that i can't solve. We did a lab where we had a pipe and produced sound resonance in there, using a generator to vary the frequencies and we recorded our data.
the general formula is for the closed pipe, fn= n (v/4L) and wavelenght= 4L/n.
The question is, explain why there are 3 cases of resonance when f= 500 hz, 4 cases of resonance when f= 700 hz and 6 cases of resonance when f= 1000 hz.
the length of the pipe was around 1 metre.
the general formula is for the closed pipe, fn= n (v/4L) and wavelenght= 4L/n.
The question is, explain why there are 3 cases of resonance when f= 500 hz, 4 cases of resonance when f= 700 hz and 6 cases of resonance when f= 1000 hz.
the length of the pipe was around 1 metre.