Density distrubution and solar lifetime of the sun

In summary, Kelvin was only able to see the photosphere of the sun and did not know how the mass was distributed inside. The potential energy of the sun would change if it was a hollow shell, with it being less than in the case of uniform density. Similarly, if the outer part of the sun is just fluff, the majority of the mass would be in the center. Calculations for the lifetime of the sun would be significantly impacted if it was a hollow shell as the photosphere would have to radiate inside the shell, depleting its potential energy quicker. The factor of density distribution in the equation can be ignored for rough calculations.
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zeion
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Homework Statement



Kelvin could only see the photosphere (the glowing outer surface) of the sun, so didn't know how the mass was distributed inside
it. How would the potential energy of the sun change if it was a hollow shell? (No numbers needed; just indicate whether it
would be more or less than in the uniform density case). Similarly, what if the outer part is just fluff, so that most of the mass is
in the center? Which of these two cases makes a bigger difference to our calculation for the lifetime of the sun?


Homework Equations



Potential energy = GM^2 / r

There is a factor in this equation that depends on the density distribution within the
object (e.g. 0.6 for a uniform sphere) - but for rough calculations we can ignore that.

The Attempt at a Solution



I don't understand how this factor of density distribution fits into the equation.
But I'm assuming that if the sun was hollow it would significantly lower it's solar lifetime since the photosphere would have to radiate inside the shell as well thus depleting its potential energy quicker.
 
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On the other hand, if the outer part is just fluff, the potential energy would increase due to the concentration of mass in the center, potentially prolonging the solar lifetime. However, the difference between these two cases would depend on the actual density distribution within the sun, as the denser the center is, the more significant the change in potential energy will be. Therefore, it is difficult to determine which case would have a bigger impact on the calculation for the solar lifetime. Further research and analysis would be needed to accurately determine the effects of different density distributions on the potential energy and solar lifetime of the sun.
 

1. What is the density distribution of the sun?

The density distribution of the sun refers to the variation in density throughout the layers of the sun. The core of the sun, where nuclear fusion takes place, has the highest density, while the outer layers have lower densities. The density decreases as you move away from the center of the sun.

2. How is the density distribution of the sun measured?

The density distribution of the sun is measured using a technique called helioseismology. This involves studying the oscillations or vibrations on the surface of the sun, which can provide information about the density and structure of the interior layers of the sun.

3. What is the average density of the sun?

The average density of the sun is about 1.41 grams per cubic centimeter (g/cm3). This is much higher than the density of the Earth, which is around 5.51 g/cm3. However, compared to other stars, the sun has a relatively low density.

4. How does the density distribution of the sun affect its lifetime?

The density distribution of the sun plays a crucial role in determining its lifetime. The higher density in the core allows for more efficient fusion reactions, which provide the energy that keeps the sun shining. As the sun continues to burn through its fuel, the density will change and ultimately lead to the end of its life as a star.

5. What is the estimated lifetime of the sun?

The sun is currently about 4.6 billion years old and is estimated to have a total lifetime of around 10 billion years. It is currently in the main sequence stage of its life, where it fuses hydrogen into helium in its core. As it runs out of hydrogen, it will expand into a red giant and eventually become a white dwarf, marking the end of its life.

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