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physgrl
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Homework Statement
A capacitor has been charged by connecting it to a 24 V battery. How much work was done in charging this capacitor, when at the end of charging, its charge is 3 µC?
a. 8 µJ
b. 12 µJ
c. 36 µJ
*d. 74 µJ
Homework Equations
W=E=Q2/2C=QV/2
The Attempt at a Solution
W=E=QV/2=24V*3μC/2=36μJ
The answer key says the answer is really 74μJ, but I don't know what I did wrong.