Why Do Electric Field Lines Never Cross?

In summary: That would be the direction of the electric field. The direction of the electric field is determined by the direction of the force on a positive charge placed at that point.
  • #1
ness87
3
0
(1)Which of the following statements about electric field lines is false?

a) They are perpendicular to the surface of an isolated conductor
b) They never intersect
c) They indicate the path along which a test charge moves
d) More indicate a stronger field
e) They can be either straight or curved
f) They indicate the force on a test charge


I have no idea how to answer this
because they all seem to be true!

(2) The electric field strength at point P which is 30cm to the right of a point charge Q=-3.0x10^(-6)C is:

a) 1.3x10^5 N/C
b) 9.0x10^4 N/C
c) 3.0x10^5 N/C
d) 5.5x10^5 N/C


I know the answer to this one is (c) however, why is it positive?? when I calculate the electric field I use E=k0 x Q/(r^2) and it is a negative answer -3.0x10^5 N/C.

(3) For the previous question, the field at this point, points:

a) towards the charge Q
b) away from the charge Q
c) up
d) down


If you can help me understand the answers and why that would be useful, I can't get my head around electric fields for some reason
 
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  • #2
ness87 said:
(1)Which of the following statements about electric field lines is false?

a) They are perpendicular to the surface of an isolated conductor
b) They never intersect
c) They indicate the path along which a test charge moves
d) More indicate a stronger field
e) They can be either straight or curved
f) They indicate the force on a test charge


I have no idea how to answer this
because they all seem to be true!
Give your justification for each one being true.
(2) The electric field strength at point P which is 30cm to the right of a point charge Q=-3.0x10^(-6)C is:

a) 1.3x10^5 N/C
b) 9.0x10^4 N/C
c) 3.0x10^5 N/C
d) 5.5x10^5 N/C


I know the answer to this one is (c) however, why is it positive?? when I calculate the electric field I use E=k0 x Q/(r^2) and it is a negative answer -3.0x10^5 N/C.
They're only asking for the electric field strength which is the magnitude of the field, not the direction.
(3) For the previous question, the field at this point, points:

a) towards the charge Q
b) away from the charge Q
c) up
d) down


If you can help me understand the answers and why that would be useful, I can't get my head around electric fields for some reason
For (3); In what direction would the force be on a positive charge, placed at this point?
 

1. What is an electric field?

An electric field is a region of space that surrounds an electrically charged object. It is created by the presence of the charged object and can exert a force on other charged objects within the field.

2. How is an electric field represented?

An electric field is represented by electric field lines. These lines point in the direction of the electric field and the density of the lines represents the strength of the field.

3. What is the difference between an electric field and an electric potential?

An electric field is a physical quantity that describes the force exerted by charged objects, whereas electric potential is a scalar quantity that describes the potential energy per unit charge at a certain point in space due to the presence of an electric field.

4. How is the strength of an electric field calculated?

The strength of an electric field is calculated by dividing the force exerted on a test charge placed in the field by the magnitude of the test charge. The unit for electric field strength is volts per meter (V/m).

5. What are some real-life applications of electric fields?

Electric fields have many practical applications, such as in electronic devices, power transmission, and medical technology. They are also used in particle accelerators, electrostatic precipitators, and electrostatic motors.

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