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JJones_86
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Homework Statement
a) Puck A
b) Puck B
Homework Equations
No idea
The Attempt at a Solution
No Idea
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Where do I even start?
G01 said:You have to show some work in order to get help here. Those are the rules. "No idea" doesn't cut it, sorry.
You have to have SOME thoughts on the problem. What have you tried? What concepts does the problem involve?
catkin said:Consider the relationship between the momenta before and after collision ...
catkin said:That's what the law of conservation tells us ... and there are more than two (you wrote "both") momenta to consider.
catkin said:p = mv
Both p (momentum) and v (velocity) are vectors so it's a vector equation.
Start with the horizontal momenta, one for A before and one each for A and B after. After must be the same as before (conservation!). You don't know the magnitude of the velocities of A and B after so you'll have to call them Va and Vb (or some such) and find another equation to find their values.
I've got to go now.
Sakha said:I'm not 100% sure but I think Ma*Va+Mb*Vb=Ma*5.59
Correct.JJones_86 said:P=m*v
= 0.226kg * 5.59m/s
= 1.263314 kg*m/s
Also correct. The suffixes a, b, x and y are a smart move. Helpful to use something like 1 for before the collision and 2 for after.JJones_86 said:Vay = Va sin 37 -- for A's Y direction
Vax = Va cos 65 -- for A's X direction
Vbx = Vb cos 37 -- for B's X direction
Vby = Vb sin 65 -- For B's Y Direction
Correct but not useful in this problem.JJones_86 said:So Va = Sqrt((Vax)^2+(Vay)^2)
That's only correct if the + sign indicates vector addition.Sakha said:I'm not 100% sure but I think Ma*Va+Mb*Vb=Ma*5.59
The speed of two objects after a collision can be calculated using the conservation of momentum equation, which states that the total momentum before the collision is equal to the total momentum after the collision. This equation is represented as:
m1v1 + m2v2 = m1v1' + m2v2', where m1 and m2 are the masses of the objects and v1, v2, v1', and v2' are the initial and final velocities of the objects, respectively.
To determine the speed of two objects after a collision, you will need to know the masses of the objects, as well as their initial velocities before the collision and their final velocities after the collision. This information can be obtained through experimentation or given in a problem.
Yes, the speed of two objects after a collision can be greater than their initial speeds. This is possible if one or both of the objects experience an external force during the collision, causing their velocities to increase.
The angle of collision can affect the speed of two objects after a collision by changing the direction of their velocities. The conservation of momentum equation still applies, but it must be broken down into its x and y components to account for the change in direction.
Yes, there is a difference in calculating the speed of two objects after an elastic collision versus an inelastic collision. In an elastic collision, the kinetic energy of the system is conserved, so the objects will have the same speed after the collision as they did before. In an inelastic collision, some kinetic energy is lost and converted into other forms of energy, resulting in the objects having a lower speed after the collision.