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ChemDoodle
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We were preparing Alkene from Alcohol & were asked to calculate percentage yield.
We used 13.5 ml Cyclohexanol with 13.5 ml water & 7ml Sulfuric acid.
To calculate % yield,i need theoretical mass..
So i was calculating no.of moles of cyclohexanol & cyclohexene (the product) to get the theoretical mass.
No of moles of cylcohexanol = m/molar mass
mass = 13.5 ml x 0.926 g/ml (density) = 12.987 g
No.of moles of cyclohexanol = 12.987/100.16 = 0.136 moles
No.of moles of cyclohexne = no.of moles of cyclohexanol = 0.136 moles (from stoichiometry)
Theoretical mass of cyclohexene = n x M
=0.136 x 82.14 = 11.17104 g
Is this calculation correct?
We used 13.5 ml Cyclohexanol with 13.5 ml water & 7ml Sulfuric acid.
To calculate % yield,i need theoretical mass..
So i was calculating no.of moles of cyclohexanol & cyclohexene (the product) to get the theoretical mass.
No of moles of cylcohexanol = m/molar mass
mass = 13.5 ml x 0.926 g/ml (density) = 12.987 g
No.of moles of cyclohexanol = 12.987/100.16 = 0.136 moles
No.of moles of cyclohexne = no.of moles of cyclohexanol = 0.136 moles (from stoichiometry)
Theoretical mass of cyclohexene = n x M
=0.136 x 82.14 = 11.17104 g
Is this calculation correct?
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