- #1
imapeiceofwod
- 29
- 0
I'm given that
Copper sulfate + sodium carbonate --> copper carbonate + sodium sulfate.
Mass of Sodium Carbonate 1.460g
Volume of copper sulfate 28.50 mL
Actual yield of copper carbonate is 0.15g
The question is using your data and knowing that sodium carbonate was in excess calculate the percent yield reaction with respect to the copper carbonate precipitate.
From my understand i got to find the theoretical mass of copper carbonate produced correct? but how? Would i just find the number of moles of sodium carbonate use the mole ratio to find the moles of copper carbonate. then from their find its mass. then use the % yield formula
Copper sulfate + sodium carbonate --> copper carbonate + sodium sulfate.
Mass of Sodium Carbonate 1.460g
Volume of copper sulfate 28.50 mL
Actual yield of copper carbonate is 0.15g
The question is using your data and knowing that sodium carbonate was in excess calculate the percent yield reaction with respect to the copper carbonate precipitate.
From my understand i got to find the theoretical mass of copper carbonate produced correct? but how? Would i just find the number of moles of sodium carbonate use the mole ratio to find the moles of copper carbonate. then from their find its mass. then use the % yield formula