- #1
converting1
- 65
- 0
draw on a argand diagram [tex] |arg(z + 1)| = \dfrac{\pi}{2} [/tex]
I got the correct drawing... but I'm not sure why it's correct.
What I thought was [itex] arg(z + 1) = \dfrac{\pi}{2} [/itex] and that's a half line from the point (-1,0) going upwards, and [itex] arg(z + 1) = -\dfrac{\pi}{2} [/itex] and that's a half life from the point (-1,0) going downwards. Joining these we get a straight line passing through the point (-1,0).
this gives the correct sketch according to my book, but what I don't understand is how we can just "add" these two graphs together - and perhaps if someone could explain a better way of thinking about it?
I got the correct drawing... but I'm not sure why it's correct.
What I thought was [itex] arg(z + 1) = \dfrac{\pi}{2} [/itex] and that's a half line from the point (-1,0) going upwards, and [itex] arg(z + 1) = -\dfrac{\pi}{2} [/itex] and that's a half life from the point (-1,0) going downwards. Joining these we get a straight line passing through the point (-1,0).
this gives the correct sketch according to my book, but what I don't understand is how we can just "add" these two graphs together - and perhaps if someone could explain a better way of thinking about it?