- #1
bomba923
- 763
- 0
Just a -very quick- clarification
Can base-1 represent a nonzero integer ?
Is there a base-1 at all?
*The digits of binary (base 2) integers contain only 0 and 1's (no 2's allowed). The digits of base-3 integers contain only 0 and 1 and 2's (no 3's allowed).
*But base-1 ? Wouldn't it contain only zeroes ? Which would not amount to anything at all?
In some sites, I read that people equate it with "tally-mark" notation. But how can that be?? A base-one integer cannot contain "1" as a digit. Therefore, there will only be a string of zeroes, which does not amount to anything at all.
0*1 + 0*(1^2) + 0*(1^3) + ... = 0, no ?
Just for clarification, is there a base-1 ?
*Can it represent nonzero integers ?
It certaintly can't equate with tally-mark notation, can it? (i.e., tally-mark notation meaning direct representation of quantity. Therefore, ||| = 3 , |||| = 4 and so on.)
Can base-1 represent a nonzero integer ?
Is there a base-1 at all?
*The digits of binary (base 2) integers contain only 0 and 1's (no 2's allowed). The digits of base-3 integers contain only 0 and 1 and 2's (no 3's allowed).
*But base-1 ? Wouldn't it contain only zeroes ? Which would not amount to anything at all?
In some sites, I read that people equate it with "tally-mark" notation. But how can that be?? A base-one integer cannot contain "1" as a digit. Therefore, there will only be a string of zeroes, which does not amount to anything at all.
0*1 + 0*(1^2) + 0*(1^3) + ... = 0, no ?
Just for clarification, is there a base-1 ?
*Can it represent nonzero integers ?
It certaintly can't equate with tally-mark notation, can it? (i.e., tally-mark notation meaning direct representation of quantity. Therefore, ||| = 3 , |||| = 4 and so on.)
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