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Color_of_Cyan
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Homework Statement
An aluminum ring of radius r1 = 5.00 cm and a resistance of 2.65 x 10^-4 Ω is placed around one end of a long air-core solenoid with 970 turns per meter and radius r2 = 3.00 cm as shown in the figure. Assume the axial component of the field produced by the solenoid is one-half as strong over the area of the end of the solenoid as at the center of the solenoid. Also assume the solenoid produces negligible field outside its cross-sectional area. The current in the solenoid is increasing at a rate of 270 A/s.
Homework Equations
ε = d(magnetic flux) / dtmagnetic flux = ∫(B)(dA)I = ε / Rmagnetic field in a solenoid:B = μ0(turns / length)(current)Ampere's law? :
∫B ds = μ0I(+ some other formula / combination I'm probably missing)
The Attempt at a Solution
I think I mostly need help just finding the induced emf (ε). I know you're to somehow find the magnetic flux of what I believe is the ring. Afterwards you find the magnetic flux and you can divide it by time (rather the time interval in which the magnetic flux changes) giving you the induced emf?
But it's complicated because there's changing current instead, which is in the solenoid, and I am not sure what to do about it, or how it relates to the change in flux over time. At the end you divide the induced emf by the resistance of the ring giving you the induced current.
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