- #1
PrudensOptimus
- 646
- 0
IS there a way to find x if given:
3^x - 3^(x-1) = 1000
I tried to take log [3^x - 3^(x-1)]/log[3] = log1000/log3
but then, x-x-1 = ...
3^x - 3^(x-1) = 1000
I tried to take log [3^x - 3^(x-1)]/log[3] = log1000/log3
but then, x-x-1 = ...