- #1
sazzy
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the speed of rotation of a point on the equator
the title is the only information I have been given to work out this questions and it relates to a2 phyics uniform circular motion and the answer is 465ms-1 I just cannot get it I know the eqautor must have something to do with it PLEASE HELP
Full calculations shown please!
the textbook gives equations speed = 2pi*r/T but I am not given radius and using the radius does not give the correct answer anyway
the closest I got was 471 ms-1 using pi/24*3600 and I just used pi because I am assuming because it asks along the equ I should use 180 degrees
the title is the only information I have been given to work out this questions and it relates to a2 phyics uniform circular motion and the answer is 465ms-1 I just cannot get it I know the eqautor must have something to do with it PLEASE HELP
Full calculations shown please!
the textbook gives equations speed = 2pi*r/T but I am not given radius and using the radius does not give the correct answer anyway
the closest I got was 471 ms-1 using pi/24*3600 and I just used pi because I am assuming because it asks along the equ I should use 180 degrees