- #1
Pantherezz
- 2
- 0
I have built a ferris wheel out of three parts, a tambourine ring, the cover that came with the tambourine, and a wooden shaft on the other side. I know that to find the kinetic energy would be Iw^2 but I don't really understand how to input the data into the equation.
I know I need to find each individual pieces' moment of inertia, using (0.5)mr^2, (0.5)m(r1^2 +r2^2). I don't know how to find the shaft's moment of inertia though...
And for the angular velocity, do you need to find each pieces separate angular velocity and add them together or do you just need it once because they would all be the same...?
See, I tried finding the answer using just the moment of inertia of the ring and the thin disk (cover) but I got a very very small number...
I know I need to find each individual pieces' moment of inertia, using (0.5)mr^2, (0.5)m(r1^2 +r2^2). I don't know how to find the shaft's moment of inertia though...
And for the angular velocity, do you need to find each pieces separate angular velocity and add them together or do you just need it once because they would all be the same...?
See, I tried finding the answer using just the moment of inertia of the ring and the thin disk (cover) but I got a very very small number...